If the temperature change is 25°C, how much heat energy in calories is released by 500 grams of water?

If the temperature change is 25°C, how much heat energy in calories is released by 500 grams of water?

• A. 12,500 calories
• B. 10,000 calories
• C. 5,000 calories
• D. 20,000 calories

Answer: (A)

To calculate the amount of heat energy released by water when it undergoes a temperature change, you can use the formula: \[ Q = m \times c \times \Delta T \] where: - \( Q \) is the heat energy in calories, - \( m \) is the mass of the water in grams, - \( c \) is the specific heat capacity of water (which is approximately 1 cal/g°C), - \( \Delta T \) is the change in temperature in degrees Celsius. In this scenario: - The mass \( m \) is 500 grams, - The specific heat capacity \( c \) of water is 1 cal/g°C, - The temperature change \( \Delta T \) is 25°C. Plugging these values into the formula: \[ Q = 500 \, \text{g} \times 1 \, \text{cal/g°C} \times 25 \, \text{°C} \] Calculating this gives: \[ Q = 500 \times 1 \times 25 = 12,500 \, \text{calories} \] Thus, the correct amount of heat energy released by 500 grams of water when the

To calculate the amount of heat energy released by water when it undergoes a temperature change, you can use the formula:

[ Q = m \times c \times \Delta T ]

where:

• ( Q ) is the heat energy in calories,

• ( m ) is the mass of the water in grams,

• ( c ) is the specific heat capacity of water (which is approximately 1 cal/g°C),

• ( \Delta T ) is the change in temperature in degrees Celsius.

In this scenario:

• The mass ( m ) is 500 grams,

• The specific heat capacity ( c ) of water is 1 cal/g°C,

• The temperature change ( \Delta T ) is 25°C.

Plugging these values into the formula:

[ Q = 500 , \text{g} \times 1 , \text{cal/g°C} \times 25 , \text{°C} ]

Calculating this gives:

[ Q = 500 \times 1 \times 25 = 12,500 , \text{calories} ]

Thus, the correct amount of heat energy released by 500 grams of water when the